Equivalent to a population evoving under the following (forward-time) reactions: \begin{align*} X & \overset{\lambda}{\longrightarrow} 2X\\ X & \overset{\mu}{\longrightarrow} 0 \end{align*} In addition, a linear sampling process $\psi$ probabilistically generates samples, but does not otherwise affect the population. (No implicit removal on sampling!)
Let $p_0(t)$ be the probability that an individual alive at time $t$ has no sampled descendents. Then: \begin{align*} p_0(t+\Delta t) \simeq & p_0(t)(1-\Delta (\lambda + \mu + \psi))\\ & + \Delta \mu + \Delta\lambda p_0(t)^2 \end{align*} and so $$\dot{p}_0(t) = -(\lambda + \psi + \mu)p_0(t) + \mu - \lambda p_0(t)^2$$
Let $g_e(t)$ be the probability that the sampled tree below time $t$ on edge $e$ evolved as observed. Then: $$\dot{g}_e(t) = -(\lambda + \psi + \mu)g_e(t) + 2\lambda p_0(t)g_e(t)$$ where
Using this in MCMC lets us jointly infer the tree and the nonlinear birth-death trajectory: